2x^2/3-10x^1/3-28=0

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Solution for 2x^2/3-10x^1/3-28=0 equation: 


x in (-oo:+oo)

(2*x^2)/3-((10*x^1)/3)-28 = 0

(2*x^2)/3+(-10/3)*x-28 = 0

2/3*x^2-10/3*x-28 = 0

DELTA = (-10/3)^2-(-28*2/3*4)

DELTA = 772/9

DELTA > 0

x = ((772/9)^(1/2)+10/3)/(2/3*2) or x = (10/3-(772/9)^(1/2))/(2/3*2)

x = 3/4*((772/9)^(1/2)+10/3) or x = 3/4*(10/3-(772/9)^(1/2))

x in { 3/4*(10/3-(772/9)^(1/2)), 3/4*((772/9)^(1/2)+10/3) }

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